Open File Dialog in C#

	
       private void folder1_Click(object sender, EventArgs e)
    {
      FolderBrowserDialog diag = new FolderBrowserDialog();
      if (diag.ShowDialog() == System.Windows.Forms.DialogResult.OK)
      {
        textBox1.Text = diag.SelectedPath;
      } 
      else
      { textBox1.Text = "You didn't select the folder!"; }
    }

    private void file_Click(object sender, EventArgs e)
    {
      OpenFileDialog openFileDialog1 = new OpenFileDialog();
      openFileDialog1.Title = "Select File";
      openFileDialog1.InitialDirectory = @"C:\";//--"C:\\";
      openFileDialog1.Filter = "All files (*.*)|*.*|Text File (*.txt)|*.txt";
      openFileDialog1.FilterIndex = 2;
      openFileDialog1.ShowDialog();
      if (openFileDialog1.FileName != "")
      { textBox1.Text = openFileDialog1.FileName; }
      else
      { textBox1.Text = "You didn't select the file!"; }
    }